The Edison storage cell is described by

Fe(s) FeO(s) KOH(aq, a_KOH) Ni₂O₃(s) NiO(s) Ni(s)

and the half-cell reactions are as follows:

Ni₂O₃(s) + H₂O(l) + 2e^– → 2NiO(s) + 2OH^– (aq)......................E^o = 0.40 V

FeO(s) + H₂O(l) + 2e^– → Fe(s) + 2OH^– (aq)..............................E^o = −0.87 V

a. What is the overall cell reaction?

b. How does the cell potential depend on the activity of the KOH?

c. How much electrical work can be obtained per kilogram of the active materials in the cell?