Question: A cannon is fired over level ground at an angle of 30 to the horizontal. The initial velocity of the cannonball is 400 m/s, but
A cannon is fired over level ground at an angle of 30° to the horizontal. The initial velocity of the cannonball is 400 m/s, but because the cannon is fired at an angle, the vertical component of the velocity is 200 m/s and the horizontal component is 346 m/s.
a. How long is the cannonball in the air? (Use g = 10 m/s2 and the fact that the total time of flight is twice the time required to reach the high point.)
b. How far does the cannonball travel horizontally?
c. Repeat these calculations, assuming that the cannon was fired at a 60° angle to the horizontal, resulting in a vertical component of velocity of 346 m/s and a horizontal component of 200 m/s. How does the distance travel compare to the earlier result?
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