An object projected from the ground at a 45 degree angle with initial velocity of 120 feet

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An object projected from the ground at a 45 degree angle with initial velocity of 120 feet per second has height, h, in terms of horizontal distance traveled, x, given by h(x) = −32/(120)² x² + x. Find the maximum height the object attains.

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Precalculus

ISBN: 9781938168345

1st Edition

Authors: Jay Abramson

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Question Posted: May 26, 2022 12:59 AM

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An object projected from the ground at a 45 degree angle with initial velocity of 120 feet

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hx 32120 2 x 2 x for the ...View the full answer

Precalculus

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