Question: A 45-caliber bullet shot straight up from the surface of the moon would reach a height of s = 832t - 2.6t 2 ft after

A 45-caliber bullet shot straight up from the surface of the moon would reach a height of s = 832t - 2.6t² ft after t sec. On Earth, in the absence of air, its height would be s = 832t - 16t2 ft after t sec. How long will the bullet be aloft in each case? How high will the bullet go?

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