A 45-caliber bullet shot straight up from the surface of the moon would reach a height of
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A 45-caliber bullet shot straight up from the surface of the moon would reach a height of s = 832t - 2.6t2 ft after t sec. On Earth, in the absence of air, its height would be s = 832t - 16t2 ft after t sec. How long will the bullet be aloft in each case? How high will the bullet go?
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Thomas Calculus Early Transcendentals
ISBN: 9780321884077
13th Edition
Authors: Joel R Hass, Christopher E Heil, Maurice D Weir
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