Question: (a) Given that lim x0 (3x + 1)(3x 1)x 2 + 0.01 = 0.01 prove that there exists an open interval (a, b) containing
(a) Given that
lim x→0 (3x + 1)(3x − 1)x2 + 0.01 = 0.01
prove that there exists an open interval (a, b) containing 0 such that (3x + 1)(3x − 1)x2 + 0.01 > 0 for all x ≠ 0 in (a, b).
(b) Given that lim x→c g(x) = L, where L > 0, prove that there exists an open interval (a, b) containing c such that g(x) > 0 for all x ≠ c in (a, b).
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a Since lim x0 3x 13x 1x2 001 001 we know that there exists a 0 such that if 0 x then 3... View full answer
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