Question: A solid of constant density is bounded below by the plane z = 0, on the sides by the elliptical cylinder x 2 + 4y

A solid of constant density is bounded below by the plane z = 0, on the sides by the elliptical cylinder x2 + 4y2 = 4, and above by the plane z = 2 - x.


a. Find x and y.


b. Evaluate the integralMxy = 2 (1/2)4-x 2-x [L -(1/2)4-x0 z dz dy dx


using integral tables to carry out the final integration with respect to x. Then divide Mxy by M to verify that z̄ = 5/4.image

Mxy = 2 (1/2)4-x 2-x [L -(1/2)4-x0 z dz dy dx

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a The elliptical cylinder can be written in terms of z as z 2 x Solving for x we get x 2 z Substitut... View full answer

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