Determine the convergence or divergence of the series. n=1 sin (2n-1)n 2
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Determine the convergence or divergence of the series.
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n=1 sin (2n-1)n 2
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2n 1 pi 2 This expression evaluates to odd multiples of pi2 which are pi2 3pi2 5pi2 and so ...View the full answer
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Related Book For
Calculus Of A Single Variable
ISBN: 9781337275361
11th Edition
Authors: Ron Larson, Bruce H. Edwards
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