Given y = (u) and u = g(x), find dy/dx = (g(x))g(x). y = 2u 3 ,
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Given y = ƒ(u) and u = g(x), find dy/dx = ƒ′(g(x))g′(x).
y = 2u3, u = 8x - 1
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Using the chain rule we can find the derivative of y with respect to x dydx dydu dudx Since y 2u3 ...View the full answer
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Related Book For
Thomas Calculus Early Transcendentals
ISBN: 9780321884077
13th Edition
Authors: Joel R Hass, Christopher E Heil, Maurice D Weir
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