Question: If a ball is thrown upward from the top of a building 128 ft high with an initial velocity of 16 ft/s, then the height

If a ball is thrown upward from the top of a building 128 ft high with an initial velocity of 16 ft/s, then the height h above the ground t seconds later will be

h = 128 + 16t - 16t²
During what time interval will the ball be at least 32 ft above the ground?

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