Question: If the switch is thrown open after the current in an RL circuit has built up to its steady-state value I = V/R, the decaying
If the switch is thrown open after the current in an RL circuit has built up to its steady-state value I = V/R, the decaying current obeys the equation
which is Equation (5) with V = 0.
a. Solve the equation to express i as a function of t.
b. How long after the switch is thrown will it take the current to fall to half its original value?
c. Show that the value of the current when t = L/R is I/e.

L + Ri = 0, dt
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a The differential equation is L didt R i 0 Divide both sides by L didt RL i 0 This ... View full answer
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