Question: Show that the function is a solution of the differential equation 00 (-1)x2 .2n f(x) = E (2n)! n=0 f(x) + (x) = 0

Show that the function00 (-1)

is a solution of the differential equationf

00 (-1)"x2" .2n f(x) = E (2n)! n=0 f"(x) + (x) = 0

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