Show that the lines 3x - 5y + 19 = 0 and 10x + 6y - 50
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Show that the lines 3x - 5y + 19 = 0 and 10x + 6y - 50 = 0 are perpendicular and find their point of intersection.
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3x5y 19 0 6y10x 50 y x 50 5y 3x 19 y x 1 m m Si...View the full answer
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