Question: Solve the differential equation using the method of variation of parameters. y'' + y = sec 2 x, 0 < x < /2
Solve the differential equation using the method of variation of parameters.
y'' + y = sec2x, 0 < x < π/2
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As in Example 5 y x C sin x c cos x so set y sinx y cos x Then yy2 y2y... View full answer
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