Suppose that (x) = x 2 and g(x) = |x|. Then the composites are both differentiable at

Suppose that ƒ(x) = x² and g(x) = |x|. Then the composites

are both differentiable at x = 0 even though g itself is not differentiable at x = 0. Does this contradict the Chain Rule? Explain.

Transcribed Image Text:

(fog)(x) = |x|² = x² and (gof)(x) = |x²| = x²