Question: Suppose that (x) = x 2 and g(x) = |x|. Then the composites are both differentiable at x = 0 even though g itself is

Suppose that ƒ(x) = x2 and g(x) = |x|. Then the composites(fog)(x) = |x| = x and (gof)(x) = |x| = x


are both differentiable at x = 0 even though g itself is not differentiable at x = 0. Does this contradict the Chain Rule? Explain.

(fog)(x) = |x| = x and (gof)(x) = |x| = x

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ANSWER No this does not contradict the Chain Rule The Chain Rule states that ... View full answer

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