The equation of a plane in space is 2(x 1) + 4(y 3) (z
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The equation of a plane in space is 2(x − 1) + 4(y − 3) − (z + 5) = 0. What is the normal vector to this plane?
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The equation of a plane in space can be written in the form ax by cz ...View the full answer
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Related Book For
Calculus Of A Single Variable
ISBN: 9781337275361
11th Edition
Authors: Ron Larson, Bruce H. Edwards
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