Question: The force F acting on a body with mass m and velocity v is the rate of change of momentum: F = (d/dt)(mv). If m

The force F acting on a body with mass m and velocity v is the rate of change of momentum: F = (d/dt)(mv). If m is constant, this becomes F = ma, where a = dv/dt is the acceleration. But in the theory of relativity the mass of a particle varies with v as follows: m = m₀/√1 - v²/c² , where m0 is the mass of the particle at rest and c is the speed of light. Show that

той F = F =. (1 – v²/c²)³/2

F = F =. (1 v/c)/2

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