Question: The function (x) = e x + x, being differentiable and one-to-one, has a differentiable inverse -1 (x). Find the value of d -1

The function ƒ(x) = e^x + x, being differentiable and one-to-one, has a differentiable inverse ƒ^-1(x). Find the value of dƒ^-1/dx at the point ƒ(ln 2).

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The inverse of x can be found by solving for x in terms of x ex x x 1ex x Taking the derivative of b... View full answer

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