Question: The height above ground of an object moving vertically is given by s = -16t 2 + 96t + 112, with s in feet and

The height above ground of an object moving vertically is given by s = -16t2 + 96t + 112, with s in feet and t in seconds. Find

a. The object’s velocity when t = 0;

b. Its maximum height and when it occurs;

c. Its velocity when s = 0.

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ANSWER a To find the objects velocity when t 0 we need to find the derivative of s with respect to t ... View full answer

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