The volume V (in cubic meters) of the hot-air balloon described in Problem 65 is given by
Question:
The volume V (in cubic meters) of the hot-air balloon described in Problem 65 is given by V(r) = 4/3πr3. If the radius r is the same function of at as in Problem 65, find the volume V as a function of the time I.
Data from problem 65
Surface Area of a Balloon The surface area S (in square meters) of a hot-air balloon is given by
S(r) = 4πr2
where r is the radius of the balloon (in meters). If the radius r is increasing with time t (in seconds) according to the formula r(t) = 2/3t3, t ≥ 0, find the surface area S of the balloon as a function of the time I.
Step by Step Answer:
Thus Vt 3281 ...View the full answer
Related Video
The area of a circle is given by the formula: A = ?r^2 Where A is the area, ? is a mathematical constant (approximately 3.14), and r is the radius of the circle. The radius is the distance from the center of the circle to the edge. So for example, if the radius of a circle is 5 units, the area would be: A = ?(5^2) = ?(25) = 78.5 square units Here three friends went out to a restaurant and decided to have pizza for lunch. While they were waiting for their order, one of them stepped out to take a call but promised to return in two minutes. The waiter came and presented them with the menu, and they decided to order two 10-inch pepperoni pizzas. The waiter took their order and left. Just then, the third friend returned and asked what they had ordered. They explained that they had ordered two small pepperoni pizzas as they were only three of them and it would be enough for them. However, the third friend suggested that for the same price, they could get a large pizza that would be much bigger than the two small ones. He asked the waiter for a pen and paper and proceeded to calculate the area of the two small pizzas and compared it to the area of one large pizza. The friends were amazed at how the circle measurements worked and decided to change their order from two small pizzas to one large pizza.
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