Question: We begin with two consecutive integers, a and a + 1, such that f(a) and f(a - 1) are of opposite sign. Evaluate f at
We begin with two consecutive integers, a and a + 1, such that f(a) and f(a - 1) are of opposite sign. Evaluate f at the midpoint m1 of a and a + 1. If f(m1) = 0, then m1 is the zero of f and we are finished. Otherwise, f(rn1) is of opposite sign to either f(a) or f(a + 1). Suppose that it is f(a) and f(m1) that are of opposite sign. Now evaluate f at the midpoint m2 of a and rn1. Repeat this process until the desired degree of accuracy is obtained. Note that each iteration places the zero in an interval whose length is half that of the previous interval. Use the bisection method to approximate the zero of f(x) = 8x4 - 2x2 + 5x - 1 in the interval [0. 1] correct to three decimal places.
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