Question: We posed a problem of finding the length L of the shortest beam that can reach over a wall of height h to a tall

We posed a problem of finding the length L of the shortest beam that can reach over a wall of height h to a tall building located k units from the wall. Use Lagrange multipliers to show that L = (h2/3 + k2/3)3/2.



Data in Section 4.6, Exercise 39


The 8-ft wall shown here stands 27 ft from the building. Find the length of the shortest straight beam that will reach to the side of the building from the ground outside the wall.Beam 8' wall -27'- Building

Beam 8' wall -27'- Building

Step by Step Solution

3.37 Rating (169 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

To find the length of the shortest beam that can reach the side of the building from the ground outs... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Precalculus Questions!