27. Translate the following C program to Pep/9 assembly language:

#include

int list[16];

int j, numItems;

int temp;

int main() {

scanf("%d", &numItems);

for (j = 0; j < numItems; j++) {

scanf("%d", &list[j]);

}

temp = list[0];

for (j = 0; j < numItems - 1; j++) {

list[j] = list[j + 1];

}

list[numItems - 1] = temp;

for (j = 0; j < numItems; j++) {

printf("%d ", list[j]);

}

printf("");

return 0;

}

Sample Input 5 11 22 33 44 55 Sample Output 22 33 44 55 11 The test in the second for loop is awkward to translate because of the arithmetic expression on the right side of the < operator. You can simplify the translation by transforming the test to the following mathematically equivalent test:

j + 1 < numItems;