Question: 13. For n = 1, 2, 3, . . . , let xn = (1)nn. Let X be a discrete random variable with theset of
13. For n = 1, 2, 3, . . . , let xn = (−1)n√n. Let X be a discrete random variable with theset of possible values A = {xn : n = 1, 2, 3, . . .} and probability mass function
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Show that even though
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does not exist.
== p(x) = P(X = x) = == 6 (TN)2
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