Question: 20. Let X and Y be discrete random variables with joint probability mass function p(x, y) = 1 e2y! (x y)! , x =

20. Let X and Y be discrete random variables with joint probability mass function p(x, y) = 1 e2y! (x − y)! , x = 0, 1, 2, . . . , y = 0, 1, 2, . . . , x, p(x, y) = 0, elsewhere. Find E(Y | X = x).

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