Question: 41. By a combinatorial argument, prove that for r n and r m, ; n + m r < = ; m 0

41. By a combinatorial argument, prove that for r ≤ n and r ≤ m, ; n + m r < = ; m 0 <;n r < + ; m 1 <; n r − 1 < + · · · + ; m r <;n 0 < .

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