Question: 4.6. Let be a standard normal random variable. (a) For an arbitrary constant a, show that E[(e - a)+] = 4 (a) - a[1 -

4.6. Let be a standard normal random variable.

(a) For an arbitrary constant

a, show that E[(e - a)+] = 4

(a) - a[1 - 4)(a)]

(b) Let X be normally distributed with mean μ and variance cr2. Show that

E[(x - b) - [6 ()- ( - ) [ - *

E[(x - b) - [6 ()- ( - ) [ - * )]} =

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