Question: Derive (1.3.4.5) from (1.2.2). n P(Bk.n) = = (x^)^ * = *. n! P k! (n-k)! P^ q (1.2.2)

Derive (1.3.4.5) from (1.2.2).n P(Bk.n) = = (x^)^ * = *. n! P k! (n-k)! P^ q (1.2.2)

n P(Bk.n) = = (x^)^ * = *. n! P k! (n-k)! P^ q (1.2.2)

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