Question: Let (F subset mathbb{R}) be a non-void perfect set, i.e. a closed set such that each point in (F) is an accumulation point of (F).

Let \(F \subset \mathbb{R}\) be a non-void perfect set, i.e. a closed set such that each point in \(F\) is an accumulation point of \(F\). Show that a perfect set is uncountable.

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