Let (left(B_{t}ight)_{t geqslant 0}) be a (mathrm{BM}^{1}). Show that (int_{0}^{T} B_{s}^{2} d B_{s}=frac{1}{3} B_{T}^{3}-int_{0}^{T} B_{s} d s,
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Let \(\left(B_{t}ight)_{t \geqslant 0}\) be a \(\mathrm{BM}^{1}\). Show that \(\int_{0}^{T} B_{s}^{2} d B_{s}=\frac{1}{3} B_{T}^{3}-\int_{0}^{T} B_{s} d s, T>0\).
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Brownian Motion A Guide To Random Processes And Stochastic Calculus De Gruyter Textbook
ISBN: 9783110741254
3rd Edition
Authors: René L. Schilling, Björn Böttcher
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