Question: Let (U subset mathbb{R}^{d}) be an open set and assume that (left(X_{t}ight)_{t geqslant 0}) is a stochastic process with continuous paths. Show that (tau_{U}=tau_{U}^{circ}).

Let \(U \subset \mathbb{R}^{d}\) be an open set and assume that \(\left(X_{t}ight)_{t \geqslant 0}\) is a stochastic process with continuous paths. Show that \(\tau_{U}=\tau_{U}^{\circ}\).

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