Prove (3.2.3) rigorously. (Advice: You may start with t p x =P(X >x+t |X >x)= P(X>x+t )/P(X>x)

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Prove (3.2.3) rigorously. (Advice: You may start with t px =P(X >x+t |X >x)= P(X>x+t )/P(X>x) = P(X>x+1)/P(X>x)  · P(X>x+t )/P(X>x+1) = P(X > x+1|X > x)P(X > x+t |X > x+1) = ....)image

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