A random variable X has a mean = 10 and a variance = 9. Using Chebyshevs theorem, find Y Y 2 1. P(|X

A random variable X has a mean μ = 10 and a variance σ =

9. Using Chebyshev’s theorem, find Y

Y 2

1. P(|X – 10| ≥ 9);

2. P(|X – 10| < 9);

3. P(4 < X < 16);

4. the value of the constant c such that P(|X – 10| ≥

c) ≤ 0.05.