Question: According to Chebyshevs theorem, the probability that any random variable assumes a value within 2 standard deviations of the mean is at least 0.75. If

According to Chebyshev’s theorem, the probability that any random variable assumes a value within 2 standard deviations of the mean is at least 0.75. If it is known that the probability distribution of a random variable X is normal, with mean μ and variance σ , what is the exact value of P(μ – 2σ < X < μ + 2σ)?

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