Question: Repeat the previous exercise using the underlying CFG of Figure 4.3. Figure 4.3 1. T TT.st := T.val E.val := TT.val 2. Ti + T

Repeat the previous exercise using the underlying CFG of Figure 4.3.

Figure 4.3

1. Е — ТT TT.st := T.val E.val := TT.val 2. ТTi + T T. + T TT2 TT2.st := TT1.st + T.val • TT1.val := TT2.val %3D 3. TTi — - Т T TT2 TT2.st := TT1.st – T.val • TT1.val := TT2.val 4. TT TT.val := TT.st 5.

1. T TT.st := T.val E.val := TT.val 2. Ti + T T. + T TT2 TT2.st := TT1.st + T.val TT1.val := TT2.val %3D 3. TTi - T TT2 TT2.st := TT1.st T.val TT1.val := TT2.val 4. TT TT.val := TT.st 5. T + F FT FT.st := F.val T.val := FT.val * F FT2 FT2.st := FT1.st x F.val 6. FT1 FT1.val := FT2.val 7. FT1 / F FT2 | FT2.st := FT1.st F.val FT1.val := FT2.val %3D 8. FT FT.val := FT.st 9. F1 - F2 F1.val := - F2.val 10. F (E ) Eval := E.val 11. F const Eval := const.val

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