Question: (a) Using only K sp from Table 6-3, calculate how many moles of Ca(OH) 2 will dissolve in 1.00 L of water. (b) How will

(a) Using only Ksp from Table 6-3, calculate how many moles of Ca(OH)2 will dissolve in 1.00 L of water.

(b) How will the solubility calculated in part (a) be affected by the K1 reaction in Table 6-3?


Table 6-3

M(OH)2(s) = M²+ + 20H Ksp = [M²*][OH¯]² M2+ + OH = MOH K¡ = [MOH*]/[M²*1[OH ] Metal log Kp log K, Mg2+ 2+ Са -11.15 2.58 -5.19 1.30 Sr+ 0.82 2+ 0.64 NOTE: 25°C and ionic strength = 0.

M(OH)2(s) = M+ + 20H Ksp = [M*][OH] M2+ + OH = MOH K = [MOH*]/[M*1[OH ] Metal log Kp log K, Mg2+ 2+ -11.15 2.58 -5.19 1.30 Sr+ 0.82 2+ 0.64 NOTE: 25C and ionic strength = 0.

Step by Step Solution

3.38 Rating (164 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

Ksp is calculated for CaOH2 If s is solubility of C... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Elementary Principles Chemical Questions!