Verify the following calculations:
a. 3.1415 (±0.0011)=1.772 4 (±0.000 3) √3.141 5 (±0.0011) = 1.772 4 (±0.0003)
b. log[3.141 5 (±0.001 1)]=0.497 14 (±0.000 15)log[3.141 5 (±0.0011)] = 0.4971₄ (±0.000 1₅)
c. antiog[3.141 5 (±0.001 1)]=1.385 (±0.004)x103antilog[3.141 5 (±0.001 1)] = 1.385 (±0.004)x10³
d. ln[3.141 5 (±0.001 1)]=1.144 7 (±0.000 4)ln[3.141 5 (±0.001 1)] = 1.144 7 (±0.000 4)
e. log(0.104 (±0.006)0.051 1 (±0.000 9))=0.800 (±0.015)

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log 0.104 (+0.006) 0.051 1 (0.000 9) = 0.800 (±0.015)