A 5.00 mL sample of brandy was diluted to 1.000 L in a volumetric flask. The ethanol, C ₂ H ₅ OH, in a 25.00 mL aliquot of the diluted solution was distilled into 50.00 mL of 0.02 M K ₂ Cr ₂ O ₇ and oxidized to acetic acid with heating, the reaction is: 3C ₂ H ₅ OH+2Cr ₂ O ₇ ^2- +16H ⁺ -->4Cr ³⁺ +3CH ₃ COOH+11H ₂ O After cooling, 20.00 mL of 0.1253 M Fe ²⁺ was pipetted into the flask. The excess Fe ²⁺ was then titrated with 7.46 mL of the K ₂ Cr ₂ O ₇ solution to a diphenylamine sulfonic acid end point. Calculate the percent weight/volume of C ₂ H ₅ OH in the brandy.

C ₂ H ₅ OH: FM=46.07 g/mol

Answer rating: 100% (QA)

Amount K 2 Cr 2 O 7 5000 746 mL x 002000 11492 nunol K 2 ... View the full answer