A sky diver of mass 51 kg can slow herself to a constant speed of 97 km/h by orienting her body horizontally, looking straight down with arms and legs extended. In this position, she presents the maximum cross-sectional area and thus maximizes the air-drag force on her.
(a) What is the magnitude of the drag force on the sky diver?


(b) If the drag force is equal to bv2, what is the value of b?

(c) At some instant she quickly flips into a "knife" position, orienting her body vertically with her arms straight down. Suppose this reduces the value of b to 57 percent of the value in Parts (a) and (b). What is her acceleration at the instant she achieves the "knife" position?

Answer rating: 100% (QA)

Given that the mass of diver is m 51 kg Speed of diver is v 97 kmh 97kmh10 3 mkm1h3600s 2694 ms ... View the full answer