A standard pendulum of length L swinging under only the influence of gravity (no resistance) has a period of

Where w2 = g/L, k2 = sin2 (60/2), g 9.8 m/s2 is the acceleration due to gravity, and GO is the initial angle from which the pendulum is released (in radians) Use numerical integration to approximate the period of a pendulum with L = 1 m that is released from an angle of 90 = 77/4 rad.

Transcribed Image Text:

- 1/5/² T = dp V1-² sin² 2 - 1/5/² T = dp V1-² sin² 2

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Given the time period of the pendu... View the full answer