A volume of water was heated to 83.38 °C and immediately added to 50.24 mL of water at 24.09 °C contained within a coffee cup calorimeter. The final temperature of the mixture was 35.63 °C. The final volume of water inside the calorimeter was 94.66 mL. Assuming that them heat capacity of the solution is 4.18 J/g/°C, calculate the following:

a. The volume of hot water added
…………..ml

b. The mass of hot water (dwater = 1.00 g/mL)
…………g
c. The mass of the cold water (dwater = 1.00 g/mL)
…………g
d. The change in temperature (AT) of hot water
.............°C
e. The change in temperature (AT) of cold water
………..°C
f. The calorimeter constant in J/°C (CD(water) = 4.18 J/g/°C)

………..°C

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Given Total volume 9466 mL Volume of cold water 5024 mL Initial temperature of hot water 8338C Initi... View the full answer