An analysis of a circuit shown in Fig yields the quadratic equation for the current I as 3 I 2 6 I 45, where I is in amps (a) Rewrite the above equation in the form of I 2 a I b 0, where a and b are constants (b) Solve the equation in par (a) by each of the following methods factoring, completing t...

a 3I 2 6I 45 3I 2 6I 450 I 2 63I 4530 I 2 2I 15 ...

An analysis of a circuit shown in Fig yields the quadratic equation for the current I as

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An analysis of a circuit shown in Fig yields the quadratic equation for the current I as 3 I ²+ 6 I = 45, where I is in amps.

(a) Rewrite the above equation in the form of I ²+ a I + b = 0, where a and b are constants.

(b) Solve the equation in par (a) by each of the following methods: factoring, completing the square, and the quadratic formula

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Thermodynamics for Engineers

ISBN: ?978-1133112860

1st edition

Authors: Kenneth A. Kroos, Merle C. Potter

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Posted Date: Nov 25, 2018 11:28 PM

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An analysis of a circuit shown in Fig yields the quadratic equation for the current I as

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Thermodynamics for Engineers

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