At 100K the reaction below obeys the rate law = k[AB2] ^ 2 where k = 5.7
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At 100K the reaction below obeys the rate law = k[AB2] ^ 2 where k = 5.7 m-1 s-1
2AB 2 --->A 2 +2B 2
What would the concentration of AB 2 be after 60 minutes if the initial concentration was 1.45 mol/L ?
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