Consider a 500-N weight suspended by two wires as shown in the figure. Find the magnitude and components of the force vectors F ₁ and F ₂ .

|F ₁ | = ?

Transcribed Image Text:

F1 45 500-N F₂ Sin(20) + F₂Sin(45) = 500N -F₂ Cos(20) + F₂ Cost(45) = 0 Cos(20) = F₂Cost(45) F = F₂Cost(45)/Cos(20) (F₂Cost(45)/Cos(20))Sin(20) + F₂ Sin(45) = 500N F₂Cos(45) + F₂Sin(45) = 500N F₂ = 500 Cos(45) + Sin(45) F₁ = 266.04 = 353.553 F1 45 500-N F₂ Sin(20) + F₂Sin(45) = 500N -F₂ Cos(20) + F₂ Cost(45) = 0 Cos(20) = F₂Cost(45) F = F₂Cost(45)/Cos(20) (F₂Cost(45)/Cos(20))Sin(20) + F₂ Sin(45) = 500N F₂Cos(45) + F₂Sin(45) = 500N F₂ = 500 Cos(45) + Sin(45) F₁ = 266.04 = 353.553

Answer rating: 100% (QA)

The re... View the full answer