Consider a machine that is subject to failures (with rate 1) and repairs (with rate 10 if the repairman is not drunk). The repairman alternates between being drunk and not drunk with rates 3 and 6. Consider a Markov pure jump process on {3, b, d, db}. (In the state's name the letter "b" means broken, and "d" means drunk.)

[The machine breaks after exponentially distributed random time with mean 30 days; if the repairman is not drunk, the time it takes to fix the machine is exponentially distributed with mean 3 days; the repairman starts drinking after exponentially distributed random time with mean 10 days; the time it takes the repairman to sober up is exponentially distributed with mean 5 day. ]

Transcribed Image Text:

d 3 10 6 b db) 3 d 3 10 6 b db) 3

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Let states by bddb and their prob by p 1 p 2 p 3 p 1 respectively at ... View the full answer