Consider a standard 8 x 8 checkerboard that is defective in the sense that two squares in opposite corners have been removed. You are given a box of dominoes (wooden rectangles) each of which covers exactly two squares of the checkerboard. Prove that it is impossible to cover all the squares of the defective board with dominoes. [Hut Squares in opposite corners have the same color. Proof by contradiction.]

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On a standard checker board there are a total of 64 squares 32 squares of one co... View the full answer