For the circuit shown, x(t) is the input and y(t) is the output voltage respectively. x(t)=10sin(? t + ?/3) + 5cos(? t + ?/6);

Find the output voltage y(t). Some useful formula - sin(x) = cos(x-?/2);

Transcribed Image Text:

x (t) +j10 Mª 10 -j10 y (t) x (t) +j10 Mª 10 -j10 y (t)

Answer rating: 100% (QA)

xt10sin t 3 5cos t ... View the full answer