Let CP denote carcinogenic potential, TR test results, and FR field result. Suppose that for Figure 7.23 we have the following probabilities.

Find the following:

a. P(TR Positive and FR positive | CP High)

b. P(TR Positive and FR negative | CP High)

c. P(TR negative and FR negative| CP Low)

d. P(TR negative and FR positive | CP Low)

Transcribed Image Text:

P(CP High) = 0.27 P(TR Positive | CP High) = 0.82 P(TR Negative | CP High) = 0.18 P(FR Positive | CP High) = 0.95 P(FR Negative | CP High) = 0.05 P(CP Low) = 0.73 P(TR Positive | CP Low) = 0.21 P(TR Negative | CP Low) = 0.79 P(FR Positive | CP Low) = 0.17 P(FR Negative | CP Low) = 0.83 Carcinogenic do od Risk Test Results Field Results P(CP High) = 0.27 P(TR Positive | CP High) = 0.82 P(TR Negative | CP High) = 0.18 P(FR Positive | CP High) = 0.95 P(FR Negative | CP High) = 0.05 P(CP Low) = 0.73 P(TR Positive | CP Low) = 0.21 P(TR Negative | CP Low) = 0.79 P(FR Positive | CP Low) = 0.17 P(FR Negative | CP Low) = 0.83 Carcinogenic do od Risk Test Results Field Results

Answer rating: 100% (QA)

A CP High B CP low P TR positive Q TR negative L F... View the full answer