The following information is given for water, H2O, at 1 atm:

boiling point = 100 °C

Hvap(100 °C) = 40.7 kJ/mol

melting point = 0.00 °C

Hfus(0.00 °C) = 6.01 kJ/mol

specific heat liquid = 4.18 J/g°C

At a pressure of 1 atm, ________kJ of heat are needed to vaporize a 35.0 g sample of liquid water at its normal boiling point of 100 °C.

Answer rating: 100% (QA)

Molar mass of H 2 O MM 2 MMH 1 MMO 2 1008 1 160 1... View the full answer