The wait time (after a scheduled arrival time) In minutes for a train to arrive is Uniformly distributed over the interval [0, 15]. You observe the wait time for the next 95 trains to arrive. Assume wait times are independent.
Part a) What is the approximate probability (to 2 decimal places) that the sum of the 95 wait times you observed is between 670 and 796?
Part b) What is the approximate probability (to 2 decimal places) that the average of the 9S wait times exceeds 7 minutes?
Part c) Find the probability (to 2 decimal places) that 92 or more of the 95 wait times exceed 1 minute.
Please carry answers to at least 6 decimal places In intermediate steps.
Part d) Use the Normal approximation to the Binomial distribution (with continuity correction) to find the probability (to 2 decimal places) that 56 or more of the 95 wait times recorded exceed 5 minutes

Answer rating: 100% (QA)

a Average sum of 95 wait times 95 0 152 7125 and std deviaiton ... View the full answer