Question: Regression Equation body_mass_g = -459 +369.4bill_depth_mm Coefficients Term Coef SE Coef T-Value P-Value VIF Constant -459 487 -0.94 0.348 bill_depth_mm 369.4 32.5 11.38 0.000 1.00
Regression Equation
| body_mass_g | = | -459 +369.4bill_depth_mm |
|---|
Coefficients
| Term | Coef | SE Coef | T-Value | P-Value | VIF |
|---|---|---|---|---|---|
| Constant | -459 | 487 | -0.94 | 0.348 | |
| bill_depth_mm | 369.4 | 32.5 | 11.38 | 0.000 | 1.00 |
Model Summary
| S | R-sq | R-sq(adj) | R-sq(pred) |
|---|---|---|---|
| 351.766 | 51.71% | 51.31% | 50.06% |
Analysis of Variance
| Source | DF | Adj SS | Adj MS | F-Value | P-Value |
|---|---|---|---|---|---|
| Regression | 1 | 16031778 | 16031778 | 129.56 | 0.000 |
| bill_depth_mm | 1 | 16031778 | 16031778 | 129.56 | 0.000 |
| Error | 121 | 14972470 | 123739 | ||
| Lack-of-Fit | 37 | 4360985 | 117864 | 0.93 | 0.583 |
| Pure Error | 84 | 10611484 | 126327 | ||
| Total | 122 | 31004248 |
Fits and Diagnostics for Unusual Observations
| Obs | body_mass_g | Fit | Resid | Std Resid | ||
|---|---|---|---|---|---|---|
| 14 | 5850.0 | 4934.8 | 915.2 | 2.61 | R | |
| 15 | 4200.0 | 4934.8 | -734.8 | -2.10 | R | |
| 18 | 6300.0 | 5156.5 | 1143.5 | 3.26 | R | |
| 21 | 5700.0 | 4824.0 | 876.0 | 2.51 | R | |
| 27 | 4100.0 | 4824.0 | -724.0 | -2.07 | R | |
| 38 | 5250.0 | 5932.3 | -682.3 | -1.99 | X | |
| 86 | 5600.0 | 5932.3 | -332.3 | -0.97 | X |
R Large residual X Unusual X
1. The first penguin in this sample had a bill depth of 13.2 mm. Using the regression equation you provided above, compute the predicted body mass for this penguin. Show your work.
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2. The first penguin in this sample had an actual body mass of 4500 grams. Using this value and the predicted value you computed in the previous question, compute the residual for the first penguin in this sample.
Hint: residual = actual body mass in the data set - predicted body mass
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